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Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismBiot-savart's & Ampere's Circuital lawEasy2 minPYQ_2014

PhysicsEasysingle choice

A circular current carrying coil has a radius $R$ . The distance from the centre of the coil on the axis, where the magnetic induction will be $\frac{1}{8}$ th to its value at the centre of the coil is

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Solution:

Here the ratio, $\frac{B _{Centre}}{B _{axis}} = (1 + \frac{x ^{2}}{R ^{2}})^{3/2}$ Also, $B_{axis} = \frac{1}{8} B_{centre}$ $\frac{8}{1} = (1 + \frac{x ^{2}}{R ^{2}})^{3/2} \Rightarrow 4 = 1 + \frac{x ^{2}}{R ^{2}} 3 = \frac{x ^{2}}{R ^{2}} \Rightarrow X^{2} = 3 R^{2} or, x = 3 R$

Stream:VITEEESubject:PhysicsTopic:MagnetismSubtopic:Biot-savart's & Ampere's Circuital law

⏱ 2mℹ️ Source: PYQ_2014

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