In hydrogen a atom, an electron is revolving in the orbit of radius 0.53 A ˚ with 6.6 × 1 0 15 radiations/s. Magnetic field produced at the centre of the orbit is

The magnetic field B = 4 π μ 0 ⋅ r 2 π ( qv ) = 1 0 − 7 × 0.53 × 1 0 − 10 2 × 3.14 × ( 1.6 × 1 0 − 19 × 1.6 × 1 0 15 ) = 12.5 Wb / m 3

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Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismMagnetic ForceMedium2 minPYQ_2012

PhysicsMediumsingle choice

In hydrogen a atom, an electron is revolving in the orbit of radius $0.53 \overset{˚}{A}$ with $6.6 \times 1 0^{15}$ radiations/s. Magnetic field produced at the centre of the orbit is

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Solution:

The magnetic field $B = \frac{μ _{0}}{4 π} \cdot \frac{2 π ( qv )}{r} = 1 0^{- 7} \times \frac{2 \times 3.14 \times ( 1.6 \times 1 0 ^{- 19} \times 1.6 \times 1 0 ^{15} )}{0.53 \times 1 0 ^{- 10}} = 12.5 Wb / m^{3}$

Stream:VITEEESubject:PhysicsTopic:MagnetismSubtopic:Magnetic Force

⏱ 2mℹ️ Source: PYQ_2012

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