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Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismMagnetic ForceEasy2 minPYQ_2012

PhysicsEasysingle choice

A proton carrying $1 MeV$ kinetic energy is moving in a circular path of radius $R$ in uniform magnetic field. What should be the energy of an $α$ -particle to describe a circle of same radius in the same field?NEET 2012 (Mains)

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Answer:

Solution:

For proton $r = \frac{2 m ( KE )}{qB}$ So $q \propto m (KE)$ Hence $\frac{e}{2 e} \frac{1}{4} KE = \frac{( m _{p} ) ( 1 MeV )}{( 4 m _{p} ) ( KE )} = \frac{1 MeV}{4 KE} = 1 MeV$

Stream:NEETSubject:PhysicsTopic:MagnetismSubtopic:Magnetic Force

⏱ 2mℹ️ Source: PYQ_2012

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