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Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismMagnetic Dipole & MomentMedium2 minPDF

PhysicsMediumnumerical range

A conducting solid sphere of radius $R$ and mass $M$ carries a charge $Q$ . The sphere is rotating about an axis passing through its center with a uniform angular speed $ω$ . The ratio of the magnitudes of the magnetic dipole moment to the angular momentum about the same axis is given as $α \frac{Q}{2 M}$ . The value of $α$ is $____$ .

Answer:

1.65

Solution:

$d I = σ R^{2} ω sin θ d θ$

$M = \int d I π R^{2} sin^{2} θ = \frac{Q R ^{2} ω}{3}$

$L = \frac{2}{5} M R^{2} ω$

$\frac{M}{L} = \frac{5}{3} \frac{Q}{2 M}$

$α = \frac{5}{3} \approx 1.67$

Stream:JEESubject:PhysicsTopic:MagnetismSubtopic:Magnetic Dipole & Moment

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