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Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismMagnetic Dipole & MomentMedium2 minQB

PhysicsMediumnumerical

A magnetic needle of magnetic moment $7.5 \times 1 0^{- 2} Am^{2}$ and moment of inertia $7.5 \times 1 0^{- 6} kg m^{2}$ is performing simple harmonic oscillations in a magnetic field of 0.1 T . Time taken for 10 complete oscillations is (Take $π^{2} = 10$ ) :

Answer:

2.00

Solution:

$T = 2 π \frac{I}{MB}$

$I = 7.5 \times 1 0^{- 6} kg - m^{2}$ , $M = 7.5 \times 1 0^{- 2} A m^{2}$

Substituting: $T = \frac{1}{5}$ s per oscillation

For 10 oscillations: time $= 10 T = 2$ s

Answer: 2.00

Stream:JEESubject:PhysicsTopic:MagnetismSubtopic:Magnetic Dipole & Moment

⏱ 2mℹ️ Source: QB

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