The helium and argon are put in the flask at the same room temperature ( 300 K). The ratio of average kinetic energies (per molecule) of helium and argon is :
(Give : Molar mass of helium $= 4 g / mol$ , Molar mass of argon $= 40 g / mol$ )

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Answer:

D

Solution:

$K . E = \frac{f}{2} K T$
For He and $Ar f = 3$
$\frac{K \cdot E _{He}}{K \cdot E _{Ar}} = \frac{1}{1}$

TestHub · Accepted Answer

K . E = 2 f ​ K T For He and Ar f = 3 K ⋅ E Ar ​ K ⋅ E He ​ ​ = 1 1 ​

Physics - Heat & Thermo Question with Solution | TestHub

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