Two particles P and Q are launched simultaneously as shown in figure. Find the minimum distance between particles in meters.

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TestHub · Accepted Answer

v PQ ​ = v P ​ − v Q ​ ​ = ( 2 ​ 10 ​ i ^ + 2 ​ 10 ​ j ^ ​ ) − ( − 2 ​ 70 ​ i ^ + 2 ​ 70 ​ j ^ ​ ) = 40 2 ​ i ^ − 30 2 ​ j ^ ​ ​ ​ A B = 90 × 3 4 ​ = 120 m ⇒ QB = 10 m ⇒ QM = 10 sin 3 7 ∘ = 10 × 5 3 ​ = 6 m ​

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