A projectile is projected with the velocity of ( 3 i ^ + 4 j ^ ) m / s . The horizontal range of the projectile will be

Given, v = 3 i ^ + 4 j ^ ∴ v = ∣ v ∣ = 3 2 + 4 2 ⇒ v = 5 m / s From figure, sin θ = 5 4 and cos θ = 5 3 ∵ R = g v 2 s i n 2 θ = g v 2 ⋅ 2 s i n θ ⋅ c o s θ = 10 5 × 5 × 2 × 5 4 × 5 3 = 24 m

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PhysicsKinematics2-D & 3DMedium2 minPYQ_2022

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A projectile is projected with the velocity of $(3 \hat{i} + 4 \hat{j}) m / s$ . The horizontal range of the projectile will be

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Given, $v = 3 \hat{i} + 4 \hat{j}$ $∴ v = ∣ v ∣ = 3^{2} + 4^{2} \Rightarrow v = 5 m / s$ From figure,
$sin θ = \frac{4}{5}$ and $cos θ = \frac{3}{5}$ $∵ R = \frac{v ^{2} s i n 2 θ}{g}$ $= \frac{v ^{2} \cdot 2 s i n θ \cdot c o s θ}{g}$ $= \frac{5 \times 5 \times 2 \times \frac{4}{5} \times \frac{3}{5}}{10} = 24 m$

Stream:BITSATSubject:PhysicsTopic:KinematicsSubtopic:2-D & 3D

⏱ 2mℹ️ Source: PYQ_2022

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