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Physics - Kinematics Question with Solution | TestHub

PhysicsKinematics1-DMedium2 minQB

PhysicsMediumsingle choice

A train $200$ m long moving with constant acceleration crosses a bridge $300$ m long. It enters the bridge with a speed of $3 m / s$ and leaves it with a speed of $5 m / s$ . The time taken to cross the bridge is:

Options:

Answer:

Solution:

The train must cover $200 + 300 = 500$ m. From $v^{2} = u^{2} + 2 a s$ : $25 = 9 + 1000 a$ , so $a = 0.016 m / s^{2}$ ; then $t = \frac{v - u}{a} = \frac{2}{0.016} = 125$ s (equivalently $t = \frac{500}{( 3 + 5 ) /2} = 125$ s). Option C.

Stream:JEESubject:PhysicsTopic:KinematicsSubtopic:1-D

⏱ 2mℹ️ Source: QB

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