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PhysicsKinematics1-DMedium2 minPYQ_2021
PhysicsMediumsingle choice

The instantaneous velocity of a particle moving in a straight line is given asv=αt+βt2, whereαandβare constants. The distance travelled by the particle between1 sand2 sis:

Options:

Answer:
B
Solution:

V=αt+βt2

dsdt=αt+βt2

S1S2 ds=12αt+βt2dt

S2-S1=αt22+βt3312

As the particle is not changing direction So distance = displacement. Distance =α[4-1]2+β[8-1]3

=3α2+7β3

Stream:JEESubject:PhysicsTopic:KinematicsSubtopic:1-D
2mℹ️ Source: PYQ_2021

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