Physics - Kinematics Question with Solution | TestHub

PhysicsKinematics2-D & 3DMedium2 minPYQ_2025

PhysicsMediumsingle choice

A ball of mass 100 g is projected with velocity $20 m / s$ at $6 0^{\circ}$ with horizontal. The decrease in kinetic energy of the ball during the motion from point of projection to highest point is

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Answer:

Solution:

$k_{i} = \frac{1}{2} mv^{2} k_{f} = \frac{1}{2} m (v cos 6 0^{\circ})^{2} = \frac{1}{8} m v^{2} Δ k = k_{i} - k_{f} = \frac{3}{8} mv^{2} = \frac{3}{8} \times 0.1 \times 400 = 15 J$

Stream:JEESubject:PhysicsTopic:KinematicsSubtopic:2-D & 3D

⏱ 2mℹ️ Source: PYQ_2025

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