A particle projected from the ground passes two points, which are at heights h 1 = 12 m and h 2 = 18 m above the ground and a distance d = 10 m apart. What could be the minimum speed of projection

Question

A particle projected from the ground passes two points, which are at heights $h_{1} = 12 m$ and $h_{2} = 18 m$ above the ground and a distance $d = 10 m$ apart. What could be the minimum speed of projection ? (m/s) (g = 10 $m / s^{2}$ ).

Answer:

20

Solution:

$v = g (h_{1} + h_{2} + d)$

$v = 10 \times 40 = 20 m / s$

TestHub · Accepted Answer

v = g ( h 1 ​ + h 2 ​ + d ) ​ v = 10 × 40 ​ = 20 m / s

Physics - Kinematics Question with Solution | TestHub

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