Physics - Kinematics Question with Solution | TestHub

For motion starting from rest ($u=0$) with constant acceleration $a$,

$S_1=\frac{1}{2}a(5{)}^2=\frac{25}{2}a$.

Distance in the first 10 seconds:$S_{10}=\frac{1}{2}a(10{)}^2=\frac{100}{2}a=4S_1$.

Distance in the next 5 seconds (i.e., from$t=5$ to $t=10\text{ s}$) is $S_2=S_{10}-S_1=4S_1-S_1=3S_1$. Therefore, the ratio$S_2/S_1=3/1$.