Physics - Kinematics Question with Solution | TestHub

Comparing with $y=x\text{tan}\theta -\frac{g{x}^2}{2u^2{\text{cos}}^2\theta }$: $\text{tan}\theta =1$, so $\theta =45^{\circ }$; range = $1$ m; $u=\sqrt{10}$ m/s, $T=\frac{2\sqrt{10}\text{sin}45^{\circ }}{10}=0.45$ s, not 0.5 s; $H=0.25$ m. Option C.