Physics - Kinematics Question with Solution | TestHub

PhysicsKinematics1-DEasy2 minPYQ_2023

PhysicsEasysingle choice

The distance travelled by a particle is related to time $t$ as $x = 4 t^{2}$ . The velocity of the particle at $t = 5 s$ is

Answer:

Solution:

Given here, $x = 4 t^{2}$

We know that velocity is the rate at which displacement changes with time. So, $v = \frac{d x}{d t} = \frac{d (4 t^{2})}{d t} = 8 t$

Now, at $t = 5 s$

Velocity of particle is $v = 8 \times 5 = 40 m s^{- 1}$ .

Stream:JEESubject:PhysicsTopic:KinematicsSubtopic:1-D

⏱ 2mℹ️ Source: PYQ_2023

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