An elevator is moving upward with a constant speed of 10 m/s. A man standing in the elevator drops a coin from a height of 2.5 m from floor of elevator. The coin reaches the floor of the elevator afte

Question

An elevator is moving upward with a constant speed of 10 m/s. A man standing in the elevator drops a coin from a height of 2.5 m from floor of elevator. The coin reaches the floor of the elevator after a time 2 ​ t ​ sec . What is the value of t ?

TestHub · Accepted Answer

The lift moves at constant speed, so its frame is inertial.

The coin begins at rest relative to the lift floor.

$2.5 = \frac{1}{2} g t_{fall}^{2}$

$t_{fall} = \frac{5}{10} = \frac{1}{2} s$

$\frac{t}{2} = \frac{1}{2} \Rightarrow t = 1$

Physics - Kinematics Question with Solution | TestHub

Doubts & Discussion

JEE Main 2028 (Class 11)