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Physics - Kinematics Question with Solution | TestHub

PhysicsKinematics1-DMedium2 minQB

PhysicsMediumsingle choice

Passage / Comprehension

A student designed a rocket that was launched straight up into the air from the ground. At $t = 0$ , the rocket is at $y = 0$ with $V_{y} (t = 0) = 0$ . The velocity of the rocket is given by: $V_{y} = (24 t - 3 t^{2}) m / s$ for $0 \leq t \leq t_{b}$ , where $t_{b}$ is the time at which the fuel burns out. The vertically upward direction is taken as positive. (Assume $g = 10 m / s^{2}$ )

The expression for the acceleration $a_{y} (t)$ valid at all times in the interval $0 < t < t_{b}$ is

Options:

Answer:

Solution:

$a_{y} = \frac{d V _{y}}{d t}$

Stream:JEESubject:PhysicsTopic:KinematicsSubtopic:1-D

⏱ 2mℹ️ Source: QB

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