In a similar symmetric arrangement, the central mass moves down with v 1 = 2 m/s and the strings each make θ = 6 0 ∘ with the central line, with the constraint v 2 = 2 v 1 cos θ . The velocity v 2 of the hanging mass m 2 is:

v 2 = 2 × 2 × cos 6 0 ∘ = 2 m/s. Option B.

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PhysicsKinematics2-D & 3DMedium2 minQB

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In a similar symmetric arrangement, the central mass moves down with $v_{1} = 2$ m/s and the strings each make $θ = 6 0^{\circ}$ with the central line, with the constraint $v_{2} = 2 v_{1} cos θ$ . The velocity $v_{2}$ of the hanging mass $m_{2}$ is:

Options:

Answer:

Solution:

$v_{2} = 2 \times 2 \times cos 6 0^{\circ} = 2$ m/s. Option B.

Stream:JEESubject:PhysicsTopic:KinematicsSubtopic:2-D & 3D

⏱ 2mℹ️ Source: QB

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