Physics - Kinematics Question with Solution | TestHub

Displacement over the interval $\mathrm{t}=0$ to $\mathrm{t}=2(2\mathrm{n}1)$ seconds. $4{\int }_0^{2(2\mathrm{n}-1)}\sin \left(\frac{\pi }{2}\mathrm{t}\right)\mathrm{dt}=-\left(\frac{8}{\pi }\right){\left|\cos \left(\frac{\pi }{2}\mathrm{t}\right)\right|}_0^{2(2\mathrm{n}-1)}$ $-\left(\frac{8}{\pi }\right)[\cos \pi (2n-1)-\cos 0]=\frac{16}{\pi }m$ $\frac{16}{2(2n-1)\pi }$ ⇒ Required average velocity $=\frac{16}{2(2n-1)\pi }$ $=\frac{8}{(2n-1)\pi }\mathrm{m}/\mathrm{s}$