A stone is thrown horizontally from the top of a tower. At a time 0.5 second after the projection the magnitude of velocity of stone is found to be 1.5 times its initial speed. If initial velocity of

Question

A stone is thrown horizontally from the top of a tower. At a time 0.5 second after the projection the magnitude of velocity of stone is found to be 1.5 times its initial speed. If initial velocity of the stone is given by $2 X (in m / s)$ then find the value of X . $(g = 10 m / s^{2})$

Answer:

5

Solution:

$u^{2} + 25 = 1.5 u$

$u = 20 u = 25$

TestHub · Accepted Answer

​ u 2 + 25 ​ = 1.5 u ​ ​ ​ u = 20 ​ u = 2 5 ​

Physics - Kinematics Question with Solution | TestHub

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