Physics - Kinematics Question with Solution | TestHub

Let $v_1=350m/s$ and $v_2=300m/s$. The horizontal components of velocities are $v_{1x}=v_1\cos (30^{\circ })$ and $v_{2x}=v_2\cos (30^{\circ })$. The relative horizontal velocity is $v_{rel,x}=v_{1x}+v_{2x}=(v_1+v_2)\cos (30^{\circ })$. The time to meet is $t=\frac{distance}{v_{rel,x}}=\frac{30}{(350+300)\cos (30^{\circ })}=\frac{30}{650\cdot \sqrt{3}/2}=\frac{60}{650\sqrt{3}}=\frac{6}{65\sqrt{3}}\approx \frac{3}{65}\sec$.

The final answer is $\boxed{3/65sec}$.