A stone is dropped from a height of 45 m from horizontal level ground. There is horizontal wind blowing due to which horizontal acceleration of the stone becomes 10 m / s 2 . (Take g = 10 m / s 2 ). F

Question

A stone is dropped from a height of 45 m from horizontal level ground. There is horizontal wind blowing due to which horizontal acceleration of the stone becomes $10 m / s^{2}$ . (Take $g = 10 m / s^{2}$ ). Find time taken by stone to reach the ground. (in $m / s$ )

Answer:

3

Solution:

$h = \frac{1}{2} g t^{2}$

$45 = \frac{1}{2} (10) t^{2}$

$45 = 5 t^{2}$

$t^{2} = 9 \Rightarrow t = 3 s$

TestHub · Accepted Answer

h = 2 1 ​ g t 2 45 = 2 1 ​ ( 10 ) t 2 45 = 5 t 2 t 2 = 9 ⇒ t = 3 s

Physics - Kinematics Question with Solution | TestHub

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