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PhysicsKinematics1-DEasy2 minPYQ_2020

PhysicsEasynumerical

A car moving with a speed of $50 km h^{- 1}$ can be stopped by brakes in at least $6 m$ . If the same car is moving at a speed of $100 km h^{- 1}$ , then the minimum stopping distance (in $m$ ) is

Answer:

24.00

Solution:

The stopping distance of a car is

$s = \frac{u^{2}}{2 a}$

Therefore, for the two situations given in the question, we can write

$\frac{s_{1}}{s_{2}} = {(\frac{u_{1}}{u_{2}})}^{2} = \frac{1}{4}$

$\frac{6}{s_{2}} = \frac{1}{4} \Rightarrow s_{2} = 24 m$

Stream:NTA_ABHYASSubject:PhysicsTopic:KinematicsSubtopic:1-D

⏱ 2mℹ️ Source: PYQ_2020

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