Physics - Kinematics Question with Solution | TestHub

In the frame of B,${\vec{v}}_{\mathrm{A}/\mathrm{B}}=20\hat{\mathrm{i}}-\frac{20}{\sqrt{3}}\hat{\mathrm{j}}$.

$\left|{\vec{v}}_{\mathrm{A}/\mathrm{B}}\right|=\frac{40}{\sqrt{3}}\mathrm{m}/\mathrm{s}$.

we have $\frac{\mathrm{OP}}{100}=\tan 30^{\circ }=\frac{1}{\sqrt{3}}$, ⟹$\mathrm{OP}=\frac{100}{\sqrt{3}}$.

$\mathrm{BQ}=\mathrm{BP}\sin \theta$.

$\mathrm{BP}=\frac{200}{\sqrt{3}}$ and $\theta =60^{\circ }$.

Since the velocity of A in the frame of B is not along B, they do not collide.