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Physics - Kinematics Question with Solution | TestHub

PhysicsKinematics1-DMedium2 minQB

PhysicsMediumsingle choice

A particle moves in a circle with constant speed $v$ . The magnitude of the change in its velocity as it moves along an arc subtending $6 0^{\circ}$ at the centre is:

Options:

Answer:

Solution:

The magnitude of the velocity change is $Δ v = 2 v sin \frac{6 0 ^{\circ}}{2} = 2 v sin 3 0^{\circ} = v$ . Option A.

Stream:JEESubject:PhysicsTopic:KinematicsSubtopic:1-D

⏱ 2mℹ️ Source: QB

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