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Physics - Kinematics Question with Solution | TestHub

PhysicsKinematics1-DHard2 minQB

PhysicsHardsingle choice

A street car starts from rest at station $A$ and moves with acceleration $f = 4 - x$ (SI units), where $x$ is the distance from $A$ . It stops at station $B$ . The distance $A B$ and the maximum velocity are:

Options:

Answer:

Solution:

$v \frac{d v}{d x} = 4 - x$ gives $\frac{v ^{2}}{2} = 4 x - \frac{x ^{2}}{2}$ ; $v = 0$ at $x = 8$ m, and $v$ peaks at $x = 4$ m with $\frac{v ^{2}}{2} = 16 - 8 = 8$ , so $v_{ma x} = 4 m / s$ . Option A.

Stream:JEESubject:PhysicsTopic:KinematicsSubtopic:1-D

⏱ 2mℹ️ Source: QB

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