Physics - Kinematics Question with Solution | TestHub

PhysicsKinematics2-D & 3DMedium2 minPYQ_2024

PhysicsMediumsingle choice

Projectiles $A$ and $B$ are thrown at angles of $45 °$ and $60 °$ with vertical respectively from top of a $400 m$ high tower. If their times of flight are same, the ratio of their speeds of projection $v_{A} : v_{B}$ is:

Options:

Answer:

Solution:

For same time of flight, vertical component of velocity of projection must be same. Therefore,
$v_{A} \sin 45 ° = v_{B} \sin 30 ° \Rightarrow \frac{v_{A}}{v_{B}} = \frac{\frac{1}{2}}{\frac{1}{\sqrt{2}}} \Rightarrow \frac{v_{A}}{v_{B}} = \frac{1}{\sqrt{2}}$

Stream:JEESubject:PhysicsTopic:KinematicsSubtopic:2-D & 3D

⏱ 2mℹ️ Source: PYQ_2024

Doubts & Discussion

Loading discussions...