A particle is moving with velocity v = K ( y i ^ + x j ^ ) , where K is a constant. The general equation for its path is

v = Ky i ^ + K x j ^ d t d x = Ky , d t d y = K x d x d y = d t d y × d x d t = Ky K x y d y = x d x y 2 = x 2 + c

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PhysicsKinematics2-D & 3DMedium2 minPYQ_2010

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A particle is moving with velocity $v = K (y \hat{i} + x \hat{j})$ , where $K$ is a constant. The general equation for its path is

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Solution:

$v = Ky \hat{i} + K x \hat{j}$ $\frac{d x}{d t} = Ky, \frac{d y}{d t} = K x$ $\frac{d y}{d x} = \frac{d y}{d t} \times \frac{d t}{d x} = \frac{K x}{Ky}$ $y d y = x d x$ $y^{2} = x^{2} + c$

Stream:JEESubject:PhysicsTopic:KinematicsSubtopic:2-D & 3D

⏱ 2mℹ️ Source: PYQ_2010

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