Home

Physics - Kinematics Question with Solution | TestHub

PhysicsKinematics1-DEasy2 minPYQ_2005

PhysicsEasysingle choice

The relation between time $t$ and distance $x$ is $t = a x^{2} + bx$ where $a$ and $b$ are constants. The acceleration is

Options:

Answer:

C

Solution:

$t = a x^{2} + b x$ by differentiating acceleration $= - 2 a v^{3}$

Stream:JEESubject:PhysicsTopic:KinematicsSubtopic:1-D

⏱ 2mℹ️ Source: PYQ_2005

Doubts & Discussion

Loading discussions...