Physics - Kinematics Question with Solution | TestHub

PhysicsKinematics1-DEasy2 minPYQ_2020

PhysicsEasysingle choice

A particle undergoes a one-dimensional motion such that its velocity varies according to $v (x) = β x^{- 2 n}$ , where $β$ and $n$ are constants and $x$ is the position of the particle. The acceleration of the particle as a function of $x$ is given by

Options:

Answer:

Solution:

According to the question

$a = v \frac{d v}{d x} = v (\frac{d}{d x} β {x}^{-2 n})$

$= (- 2 n β x^{-2 n - 1}) β x^{- 2 n}$

$= - 2 n β^{2} x^{- 4 n - 1}$

Stream:NTA_ABHYASSubject:PhysicsTopic:KinematicsSubtopic:1-D

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...