Physics - Kinematics Question with Solution | TestHub

PhysicsKinematicsMiscellaneousHard2 minQB

PhysicsHardmultiple choice

A particle is projected with a speed of 50 m/s at an angle of 37° with the horizontal from the top of a tower. Then select the CORRECT statement(s) :-

Options:(select one or more)

Answer:

A, B, D

Solution:

Equation of trajectory:

$y y y = x tan θ - \frac{1}{2} \frac{g x ^{2}}{u ^{2} cos ^{2} θ} = \frac{3 x}{4} - \frac{1}{2} \frac{10 x ^{2}}{2500 \times \frac{16}{25}} = \frac{3 x}{4} - \frac{x ^{2}}{320}$

The time after which the particle moves perpendicular to its initial velocity is:

$t t = \frac{v}{g sin θ} = \frac{50}{10 \times \frac{3}{5}} = \frac{25}{3} sec$

Stream:JEESubject:PhysicsTopic:KinematicsSubtopic:Miscellaneous

⏱ 2mℹ️ Source: QB

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