Physics - Kinematics Question with Solution | TestHub

$\text{Speed of train}=108\times \frac{5}{18}=30\text{m/s}$

Let${\overrightarrow{v}}_R\text{and}{\overrightarrow{v}}_T$represent the respective velocities of rain and train.

Now, the relative velocity of rain w.r.t person (train) is given by$v_{\text{R, T}}={\overrightarrow{v}}_R-{\overrightarrow{v}}_T\Rightarrow {\overrightarrow{v}}_R+\left(-{\overrightarrow{v}}_T\right)$

Let$\overrightarrow{\text{OR}}\text{and}\overrightarrow{\text{RT}}$represent the vectors in magnitude and direction.



OT²= OR²+ RT²+ 2OR × RT cos 120^o

$=20^2+30^2-2\times 20\times 30\times \frac{1}{2}$

$=400+900-600=700=\sqrt{700}\text{m/s}$