Physics - Kinematics Question with Solution | TestHub

PhysicsKinematics1-DMedium2 minQB

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If a particle moves along a straight line according to the law $v = 2 (x sin x + cos x)$ then find its acceleration (i.e. $\frac{d v}{d t}$ ) at $x = π /2$ :-

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Answer:

Solution:

$\frac{d v}{d t} = 2 (\frac{d x}{d t} sin x + x cos x \frac{d x}{d t} - sin x \frac{d x}{d t}) = 2 (x cos x \frac{d x}{d t}) = 2 xv cos x$

$(\frac{dx}{dt})_{\frac{π}{2}} = v = 2 x \times 2 (x sin x + cos) cos x = 2 \frac{π}{2} \times 2 (\frac{π}{2} (1) + 0) 0 = 0 \Rightarrow \frac{dv}{dt} = 0$

Stream:JEESubject:PhysicsTopic:KinematicsSubtopic:1-D

⏱ 2mℹ️ Source: QB

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