A ball is dropped vertically from a height d above the ground. It hits the ground and bounces up vertically to a height d / 2 . Neglecting subsequent motion and air resistance, its velocity v varies w

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A ball is dropped vertically from a height d above the ground. It hits the ground and bounces up vertically to a height d / 2 . Neglecting subsequent motion and air resistance, its velocity v varies with height h above the ground as

TestHub · Accepted Answer

For the uniformly accelerated/decelcrated motion,

$v^{2} = u^{2} \pm 2 g h$

So. from this equation. we can say $v - h$ paragraph is parabola.

Initially, velocity is downwards $(- v e)$ after collision, it reverses the direction with smaller magnitude and velocity is upwards $(- v e)$ .

So. graph (a) satisfies these conditions.

Also, When $t = 0, h = d$ Velocity increases downwards $(U \to A)$

When $t - 1$ velocity reverses its direction $(A^{'} \to B)$

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