If t = x + 4 , then d x d t t = 4 is:

Given that t = x + 4 ⇒ x = t - 4 2 = t 2 - 8 t + 16 Differentiating the above equation with respect to time, ⇒ d x d t = 2 t - 8 Putting the value of t = 4 ⇒ d x d t = 2 × 4 − 8 = 0

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PhysicsKinematics1-DEasy2 minPYQ_2022

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If $t = \sqrt{x} + 4$ , then ${(\frac{d x}{d t})}_{t = 4}$ is:

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Answer:

Solution:

Given that $t = \sqrt{x} + 4$
$\Rightarrow x = {(t - 4)}^{2} = t^{2} - 8 t + 16$
Differentiating the above equation with respect to time,
$\Rightarrow \frac{d x}{d t} = 2 t - 8$
Putting the value of $t = 4$
$\Rightarrow \frac{d x}{d t} = 2 \times 4 - 8 = 0$

Stream:JEESubject:PhysicsTopic:KinematicsSubtopic:1-D

⏱ 2mℹ️ Source: PYQ_2022

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