Physics - Kinematics Question with Solution | TestHub

PhysicsKinematics1-DEasy2 minQB

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A moving particle is acted upon by three forces at different times to bring it to rest. Its velocity versus time graph is given below

The average acceleration from $t = 5 s$ to $t = 15 s$ is

Answer:

Solution:

Average acceleration from $t = 5 s$ to $t = 15 s$

$= \frac{v ( t = 15 ) - v ( t = 5 )}{15 - 5} = \frac{0 - 5}{10} = - \frac{1}{2} ms^{- 2}$

Stream:JEESubject:PhysicsTopic:KinematicsSubtopic:1-D

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