A car starting from rest accelerates at the rate f through a distance S , then continues at constant speed for time t and then decelerates at the rate f /2 to come to rest. If the total distance trave

Question

A car starting from rest accelerates at the rate f through a distance S , then continues at constant speed for time t and then decelerates at the rate f /2 to come to rest. If the total distance traversed is 15 S , then

TestHub · Accepted Answer

​ S = 2 ft 1 2 ​ ​ v 0 ​ = 2 Sf ​ ​ During retardation S 2 ​ = 2 S During constant velocity ​ 15 S − 3 S = 12 S = v 0 ​ t ⇒ S = 72 ft 2 ​ ​

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