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Physics - Kinematics Question with Solution | TestHub

PhysicsKinematics2-D & 3DMedium2 minPDF

PhysicsMediumnumerical

A particle is thrown horizontally with speed 15 m/s. Find the time (in sec) at which it strikes the inclined plane as shown in figure. ( $g = 10 m / s^{2}$ )

Answer:

2.00

Solution:

$x = 15 t, y = \frac{1}{2} g t^{2}$

At impact, the coordinates satisfy the inclined-plane equation shown.

$5 t^{2} = (tan θ) (15 t)$

Using the shown angle gives t = 2 s.

Stream:JEESubject:PhysicsTopic:KinematicsSubtopic:2-D & 3D

⏱ 2mℹ️ Source: PDF

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