Two rigid boxes containing different ideal gases are placed on a table. Box A contains one mole of nitrogen at temperature T 0 , while Box B contains one mole of helium at temperature ( 7/3 ) T 0

Question

Two rigid boxes containing different ideal gases are placed on a table. Box A contains one mole of nitrogen at temperature $T_{0}$ , while Box $B$ contains one mole of helium at temperature $(7/3) T_{0}$ . The boxes are then put into thermal contact with each other and heat flows between them until the gases reach a common final temperature. (Ignore the heat capacity of boxes). Then, the final temperature of the gases, $T_{f}$ , in terms of $T_{0}$ is

Options:

Answer:

D

Solution:

$Δ U = 0$ $\Rightarrow \frac{3}{2} R (T_{f} - T_{0}) + 1 \times \frac{5}{2} R (T_{f} - \frac{7}{3} T_{0}) = 0$ $T_{f} = \frac{3}{2} T_{0}$

TestHub · Accepted Answer

Δ U = 0 ⇒ 2 3 ​ R ( T f ​ − T 0 ​ ) + 1 × 2 5 ​ R ( T f ​ − 3 7 ​ T 0 ​ ) = 0 T f ​ = 2 3 ​ T 0 ​

Physics - Heat & Thermo Question with Solution | TestHub

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