Two moles of helium are mixed with n moles of hydrogen. If C p C v = 3 2 for the mixture then the value of n is,

γ mix = 1 + 2 f mix C p C v = f m i x + 2 f m i x = 3 2 ⇒ f m i x = 4 f m i x = n 1 f 1 + n f 2 n 1 + n 2 ⇒ 4 = 2 × 3 + n × 5 2 + n ⇒ n = 2 mole

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PhysicsHeat & ThermoKTGMedium2 minQB

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Two moles of helium are mixed with n moles of hydrogen. If $\frac{C_{p}}{C_{v}} = \frac{3}{2}$ for the mixture then the value of $n$ is,

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Answer:

Solution:

$γ_{mix} = 1 + \frac{2}{f_{mix}}$

$\frac{C_{p}}{C_{v}} = \frac{f_{m i x} + 2}{f_{m i x}} = \frac{3}{2}$

$\Rightarrow f_{m i x} = 4$

$f_{m i x} = \frac{n_{1} f_{1} + n_{} f_{2}}{n_{1} + n_{2}}$

$\Rightarrow 4 = \frac{2 \times 3 + n \times 5}{2 + n}$

$\Rightarrow n = 2 mole$

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:KTG

⏱ 2mℹ️ Source: QB

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