An insulated container of gas has two chambers separated by an insulating partition. One of the chambers has volume V 1 and contains ideal gas at pressure P 1 and temperature T 1 . The other cha

Question

An insulated container of gas has two chambers separated by an insulating partition. One of the chambers has volume $V_{1}$ and contains ideal gas at pressure $P_{1}$ and temperature $T_{1}$ . The other chamber has volume $V_{2}$ and contains ideal gas at pressure $P_{2}$ and temperature $T_{2}$ . If the partition is removed without doing any work on the gas, the final equilibrium temperature of the gas in the container will be

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Answer:

A

Solution:

$U = U_{1} + U_{2} T = \frac{( P _{1} V _{1} + P _{2} V _{2} ) T _{1} T _{2}}{( P _{1} V _{1} T _{2} + P _{2} V _{2} T _{1} )}$

TestHub · Accepted Answer

​ U = U 1 ​ + U 2 ​ T = ( P 1 ​ V 1 ​ T 2 ​ + P 2 ​ V 2 ​ T 1 ​ ) ( P 1 ​ V 1 ​ + P 2 ​ V 2 ​ ) T 1 ​ T 2 ​ ​ ​

Physics - Heat & Thermo Question with Solution | TestHub

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