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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoCalorimetryMedium2 minQB

PhysicsMediumsingle choice

Two liquids A and B are at $30^{\circ} C$ and $20^{\circ} C$ . When mixed in equal masses the temperature of the mixture is found to be $26^{\circ} C$ . The ratio of specific heats of A and B is

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Answer:

Solution:

Heat lost by A equals heat gained by B.
$m c_{A} (30 - 26) = m c_{B} (26 - 20)$
$4 c_{A} = 6 c_{B}$
$c_{A} : c_{B} = 3 : 2$

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:Calorimetry

⏱ 2mℹ️ Source: QB

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