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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoThermodynamicsMedium2 minQB

PhysicsMediummultiple choice

Figure shows an indicator diagram. During path 1-2-3, 100 cal are given to the system and 40 cal work is done. During path 1-4-3, the work done is 10 cal.

Options:(select one or more)

Answer:

A, C

Solution:

$U_{3} - U_{1} = Q_{123} - W_{123} = 100 - 40 = 60$ cal (D false).

$Q_{143} = Δ U + W_{143} = 60 + 10 = 70 cal (A true).$

Along 3-1: $W_{31} = - \frac{40 + 10}{2} = - 25$ cal (B false); $Q_{31} = - 60 - 25 = - 85$ cal, i.e. 85 cal ejected (C true).

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:Thermodynamics

⏱ 2mℹ️ Source: QB

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