2 moles of an ideal monoatomic gas is expanded according to the relation $PT = co n s t an t$ from its initial state $(P_{0} V_{0})$ to the final state, due to which its pressure becomes half of the initial pressure. The change in internal energy is

Question

TestHub · Accepted Answer

Concepts: Ideal gas law ( P V = n RT ), internal energy of monoatomic gas ( Δ U = n C v ​ Δ T ), C v ​ = 2 3 ​ R . Given PT = co n s t an t and P 2 ​ = P 0 ​ /2 , we find T 2 ​ = 2 T 0 ​ . Δ U = n ( 2 3 ​ R ) ( 2 T 0 ​ − T 0 ​ ) = 2 3 ​ n R T 0 ​ = 2 3 ​ P 0 ​ V 0 ​ .

Physics - Heat & Thermo Question with Solution | TestHub

Options:

Doubts & Discussion

JEE Main (2028)