Consider the shown case of a freezing lake due to negative environmental temperature ( − θ ∘ C ) . Thickness (x) of ice layer is small in comparison to depth of lake. Rate of increase in x will be greater

dt dQ = x kA θ = ( dt dm ) L x k A θ = ρ A V L V = ( ρ L k ) x θ

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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoConductionMedium2 minQB

PhysicsMediummultiple choice

Consider the shown case of a freezing lake due to negative environmental temperature $(- θ^{\circ} C)$ . Thickness (x) of ice layer is small in comparison to depth of lake. Rate of increase in x will be greater

Options:(select one or more)

Answer:

C, D

Solution:

$\frac{dQ}{dt} = \frac{kA θ}{x} = (\frac{dm}{dt}) L$

$\frac{k A θ}{x} = ρ A V L V = (\frac{k}{ρ L}) \frac{θ}{x}$

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:Conduction

⏱ 2mℹ️ Source: QB

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