Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoConductionMedium2 minQB

PhysicsMediummultiple choice

Two ends of conducting rod of varying cross-section are maintained at 200°C and 0°C. In steady state:

Answer:

C, D

Solution:

$C = \frac{dQ}{dt} = k \frac{A Δ T}{L}$

$C = kA \frac{Δ T}{x} Δ T = \frac{Cx}{kA} Δ T < \frac{1}{A}$

cross section area at $AB > CD$

$(Δ T)_{CD} > (Δ T)_{AB}$

Temperature gradient $\frac{dT}{dx} \propto \frac{1}{A}$ As we move from A to B cross section area decreases so, temperature gradient increases.

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:Conduction

⏱ 2mℹ️ Source: QB

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