For an ideal gas a process PV diagram is a circle. An adiabat from A passes through C. An isotherm from A passes through B. We take a part of the circular cyclic process. Comment on the sign of the qu

Question

For an ideal gas a process PV diagram is a circle. An adiabat from A passes through C. An isotherm from A passes through B. We take a part of the circular cyclic process. Comment on the sign of the quantity of Column-I.

List - I	List - II
(A) Heat given to the gas in going from A to C along circle	(P) Positive
(B) Heat given to the gas in going from B to C along circle	(Q) Negative
(C) Heat given to the gas in going from C to D along circle	(R) Zero
	(S) can't be said

TestHub · Accepted Answer

A → C along the circle: expansion ( W > 0 ); C lies on the adiabat from A so Δ U < 0 , and overall Δ Q = W + Δ U > 0 (P). B → C along the circle: compression ( W < 0 ) and Δ U < 0 (B on the isotherm, C cooler), so Δ Q < 0 (Q). C → D along the circle: same as B → C, so Δ Q < 0 (Q).

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