Physics - Heat & Thermo Question with Solution | TestHub

An amount of ice of mass $10^{-3}\mathrm{kg}$ and temperature $-10^{\circ }\mathrm{C}$ is transformed to vapour of temperature $110^{\circ }\mathrm{C}$ by applying heat. The total amount of work required for this conversion is, (Take, specific heat of ice $=2100{\mathrm{Jkg}}^{-1}{\mathrm{K}}^{-1}$, specific heat of water $=4180{\mathrm{Jkg}}^{-1}{\mathrm{K}}^{-1}$, specific heat of steam $=1920{\mathrm{Jkg}}^{-1}{\mathrm{K}}^{-1}$, Latent heat of ice $=3.35\times 10^5{\mathrm{Jkg}}^{-1}$ and Latent heat of steam $=2.25\times 10^6$ ${\mathrm{Jkg}}^{-1}$ )