A gas mixture consists of 8 moles of argon and 6 moles of oxygen at temperature T . Neglecting all vibrational modes, the total internal energy of the system is

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As we know, internal energy is given by, $U = n C_{v} T$ . Also argon gas is monoatomic and oxygen gas is diatomic.

Therefore, total internal energy will be $U_{n e t} = n_{1} C_{V_{1}} T + n_{2} C_{V_{2}} T$

$= 8 \times \frac{3 R}{2} \times T + 6 \times \frac{5 R}{2} \times T$

$= 27 R T$

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