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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoSecond Law of ThermodynamicsEasy2 minPYQ_2023

PhysicsEasysingle choice

A Carnot engine has an efficiency of $50 %$ when its source is at a temperature $327 ° C .$ The temperature of the sink is:NEET 2023 (All India)

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Answer:

Solution:

Efficiency of Carnot engine is given by,
$η = 1 - \frac{T_{\sin k}}{T_{s o u r c e}} \Rightarrow \frac{50}{100} = 1 - \frac{T_{\sin k}}{(327 + 273) K} \Rightarrow T_{\sin k} = \frac{1}{2} \times 600 = 300 K = (300 - 273) ° C = 27 ° C$

Stream:NEETSubject:PhysicsTopic:Heat & ThermoSubtopic:Second Law of Thermodynamics

⏱ 2mℹ️ Source: PYQ_2023

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